运用SPSS进行信度分析
SPSS信度分析步骤
Data输入页
变项定义页
信度分析
1.再测信度(Test-Retest Reliability)
2.复本信度(Alternate-form Reliability)
3.折半信度(Split-half Reliaility)
4.內部一致性(Internal Consistency Coefficient)【计算α系数】
再测信度(Test-Retest Reliability)
步骤一 按【Analyze】→【Correlate】→【Bivariate…】
步骤二 会出现下面的对话框,将左边两变项选入右边「Variables」内,在「Correlation Coefficients」方盒内选取「□Pearson」;在「Test of Significance」方盒内选取「□Two-tailed」;勾选最下面的「□Flag significant correlations」,之后按键。
补充 若想呈现平均及标准差可在按键前按进入下个对话框,在Statistics的方盒内选取「□Means and standard deviations」,按继续。
word/media/image15.gif
Correlations
word/media/image17_1.png
word/media/image18_1.png
纸笔计算结果:
N=10
0c9797ef2becefabf0de0f678f990713.png
复本信度(Alternate-form Reliability)
Correlations
word/media/image22_1.png
word/media/image23_1.png
纸笔计算结果:
N=10
76b1ba3f25ab6472d581e9aa0a59bc0d.png
步骤一 输入资料
步骤二 转换资料为数字
按【Transform】→【Recode】→【Into Same Variables…】
出现下面的对话框后将左边方格内item1~item6选至右边String Variables内后点选键
出现下列对话框后,将”N”定义为”0”,将”Y”定义为”1”后按键
之后便会将资料转换成下面的数字
步骤三 将string的属性改为numeric
步骤四 计算奇数题和偶数题的和
按【Transform】→【Compute…】即出现下面的对话框
结束后便会在spss Data Editor对话框中出现奇数题和偶数题的和
步骤四 执行Bivariate
Correlations
word/media/image38_1.png
word/media/image39.gifword/media/image40_1.png
纸笔计算结果
Ⅰ. 计算两个”半测验”的相关
N=5
626058403c006bab676dfe06f8ce8976.png
Ⅱ 校正相关系数为折半信度
Spearmen-Brown prophesy formula 史比校正公式 (当两个半测验变异数相等时使用)
245a670776d0cefcd1c15d855224e7b0.png
4082648afd1695e3ed5a7e36dfb9a0b2.png
Guttman prophesy formula 哥德曼校正公式 (当两个半测验变异数不等时使用)
a2d4a85f74e7c3bf24dc2742f6ed316a.png
fd65ac13b16020696d8179daa6a388fc.png
*折半信度* 折半信度也可直接使用SPSS計算
步骤一 输入资料
步驟二 按【Analyze】→【Scale】→【Reliability Analysis】将左边方格内的变项依所需次序分前后半选入右边items的方格内,在左下角的Model框中选取Split-half后按键,再按。
word/media/image48.gif
Reliability
****** Method 1 (space saver) will be used for this analysis ******
R E L I A B I L I T Y A N A L Y S I S - S C A L E (S P L I T)
Reliability Coefficients
N of Cases = 5.0 N of Items = 6
word/media/image50.gifCorrelation between forms = .8729 Equal-length Spearman-Brown = .9321
Guttman Split-half = .8889 Unequal-length Spearman-Brown = .9321
3 Items in part 1 3 Items in part 2
Alpha for part 1 = -2.5000 Alpha for part 2 = .0000
Correlations
word/media/image52_1.png
Correlations
****** Method 1 (space saver) will be used for this analysis ******
R E L I A B I L I T Y A N A L Y S I S - S C A L E (S P L I T)
Reliability Coefficients
N of Cases = 5.0 N of Items = 6
word/media/image53.gifCorrelation between forms = .0000 Equal-length Spearman-Brown = .0000
Guttman Split-half = .0000 Unequal-length Spearman-Brown = .0000
>Note # 11999
>The correlation between forms (halves) of the test is negative. This
>violates reliability model assumptions. Statistics which are functions of
>this value may have estimates outside theoretically possible ranges.
3 Items in part 1 3 Items in part 2
Alpha for part 1 = -.9000 Alpha for part 2 = .6923
內部一致性(Internal Consistency Coefficient)【计算α系数】
步骤一 输入资料
步骤二 按【Analyze】→【Scale】→【Reliability Analysis】
将左边方格内的变项全选入右边items的方格内,在左下角的Model框中选取Alpha后按键。
word/media/image15.gif
步骤三 出现下列对话框候选取下列勾选后按键
按。
Reliability
****** Method 2 (covariance matrix) will be used for this analysis ******
R E L I A B I L I T Y A N A L Y S I S - S C A L E (A L P H A)
Correlation Matrix
ITEM_1 ITEM_2 ITEM_3 ITEM_4 ITEM_5
ITEM_1 1.0000
ITEM_2 .2970 1.0000
ITEM_3 .7647 .5941 1.0000
ITEM_4 .6860 .4330 .8575 1.0000
ITEM_5 .1588 .8018 .4763 .4629 1.0000
N of Cases = 6.0
Item-total Statistics
Scale Scale Corrected
Mean Variance Item- Squared Alpha
if Item if Item Total Multiple if Item
Deleted Deleted Correlation Correlation Deleted
word/media/image59.gif
ITEM_1 13.0000 6.4000 .5251 .6471 .8472
ITEM_2 13.1667 5.3667 .6757 .7500 .8116
ITEM_3 12.3333 5.4667 .8333 .8588 .7642
ITEM_4 13.5000 6.7000 .7481 .7857 .8093
ITEM_5 12.6667 5.8667 .5922 .7143 .8333
Reliability Coefficients 5 items
Alpha = .8457 Standardized item alpha = .8609
纸笔计算结果
1ce0cdaf66b9bf4b74d1f118c30080ef.png
3bdba21f3291dc3957521c0f1175acfd.png
步骤一 转换资料Y正确为1,N不正确为0
步骤二 与题四求内部ㄧ致性的步骤相同
Reliability
****** Method 2 (covariance matrix) will be used for this analysis ******
R E L I A B I L I T Y A N A L Y S I S - S C A L E (A L P H A)
Correlation Matrix
* * * Warning * * * Determinant of matrix is close to zero: 8.426E-36
Statistics based on inverse matrix for scale ALPHA
are meaningless and printed as .
N of Cases = 5.0
Item-total Statistics
Scale Scale Corrected
Mean Variance Item- Squared Alpha
if Item if Item Total Multiple if Item
Deleted Deleted Correlation Correlation Deleted
ITEM_1 2.2000 1.7000 .1400 . .2941
ITEM_2 2.2000 2.2000 -.1846 . .5114
ITEM_3 2.6000 1.3000 .6864 . -.0962
ITEM_4 2.2000 1.7000 .1400 . .2941
ITEM_5 2.6000 2.3000 -.2212 . .4891
ITEM_6 2.2000 1.2000 .5833 . -.1042
R E L I A B I L I T Y A N A L Y S I S - S C A L E (A L P H A)
Reliability Coefficients 6 items
Alpha = .3273 Standardized item alpha = .3307
纸笔计算结果
1ce0cdaf66b9bf4b74d1f118c30080ef.png
89eb84da52241d5f94d565c705df50d0.png
本文来源:https://www.2haoxitong.net/k/doc/278aafdca9114431b90d6c85ec3a87c241288a1d.html
文档为doc格式